(3x+2)(3x^2-19x+20)=0

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Solution for (3x+2)(3x^2-19x+20)=0 equation: 


Simplifying
(3x + 2)(3x2 + -19x + 20) = 0

Reorder the terms:
(2 + 3x)(3x2 + -19x + 20) = 0

Reorder the terms:
(2 + 3x)(20 + -19x + 3x2) = 0

Multiply (2 + 3x) * (20 + -19x + 3x2)
(2(20 + -19x + 3x2) + 3x * (20 + -19x + 3x2)) = 0
((20 * 2 + -19x * 2 + 3x2 * 2) + 3x * (20 + -19x + 3x2)) = 0
((40 + -38x + 6x2) + 3x * (20 + -19x + 3x2)) = 0
(40 + -38x + 6x2 + (20 * 3x + -19x * 3x + 3x2 * 3x)) = 0
(40 + -38x + 6x2 + (60x + -57x2 + 9x3)) = 0

Reorder the terms:
(40 + -38x + 60x + 6x2 + -57x2 + 9x3) = 0

Combine like terms: -38x + 60x = 22x
(40 + 22x + 6x2 + -57x2 + 9x3) = 0

Combine like terms: 6x2 + -57x2 = -51x2
(40 + 22x + -51x2 + 9x3) = 0

Solving
40 + 22x + -51x2 + 9x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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